Решите плиз даю 50 б
7(4а + 6) – 1,2а =
8х – 4(16 – 2х) =
1,7(а – 4) + 0,6(6 – 2а) =
1,5(8х – 6у) – 2,4(5у – 3х) =
–(4,3х – 2,4) – (5,8 – 2,6х) =
0,6(4х -12) – 0,4(5х – 7) =
7(4а + 6) – 1,2а =
8х – 4(16 – 2х) =
1,7(а – 4) + 0,6(6 – 2а) =
1,5(8х – 6у) – 2,4(5у – 3х) =
–(4,3х – 2,4) – (5,8 – 2,6х) =
0,6(4х -12) – 0,4(5х – 7) =
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Ответ:
Пошаговое объяснение:
7(4а + 6) – 1,2а = 28a + 42 - 1,2a = 26,8a + 42
8х – 4(16 – 2х) = 8x - 64 + 8x = 16x - 64
1,7(а – 4) + 0,6(6 – 2а) = 1,7a - 6,8 + 3,6 - 1,2a = 0,5a - 3,2
1,5(8х – 6у) – 2,4(5у – 3х) = 12x - 9y - 12y + 7,2x = 19,2x - 21y
–(4,3х – 2,4) – (5,8 – 2,6х) = -4,3x + 2,4 - 5,8 + 2,6x = -1,7x - 3,4
0,6(4х -12) – 0,4(5х – 7) = 2,4x - 7,2 - 2x + 2,8 = 0,4x - 4,4