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fedoseev2014
@fedoseev2014
August 2021
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решите плиз (с-2)(с+3)-с² и 7(x+8)+(x+8)(x-8)
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mixa1893
(с-2)(с+3)-с²
с²+3с-2с-6-
с²=0
с-6=0
с=6
7(x+8)+(x+8)(x-8)
7x+56+x
²-8x+8x-64
x
²+7x-8=0
Д= 7
²-4*1*(-8)=49+32=81=9
x1= (-7+9) / 2 = 1
x2= (-7-9) / 2 = - 8
2 votes
Thanks 2
МаргаритаКорж
С²+3с-2с-6-с²=c² сокращается поэтому
с-6=0
с=6
7х+56+х²-8х+8х-64=0
7х+56+х²-64=0
х²+7х-8=0
D=7²-4*1*(-8)=49+32=√81=9>0
x1=-7+9/14=2/14=1/7
x2=-7-9/14=-16/14=-8/7
1 votes
Thanks 0
МаргаритаКорж
ой там х1 и х2 найдены не правильно,надо поделить на 2)
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Answers & Comments
с²+3с-2с-6-с²=0
с-6=0
с=6
7(x+8)+(x+8)(x-8)
7x+56+x²-8x+8x-64
x²+7x-8=0
Д= 7²-4*1*(-8)=49+32=81=9
x1= (-7+9) / 2 = 1
x2= (-7-9) / 2 = - 8
с-6=0
с=6
7х+56+х²-8х+8х-64=0
7х+56+х²-64=0
х²+7х-8=0
D=7²-4*1*(-8)=49+32=√81=9>0
x1=-7+9/14=2/14=1/7
x2=-7-9/14=-16/14=-8/7