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andrey45981
@andrey45981
September 2021
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Решите плиз
x*√(x²-x-2)≥0
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oganesbagoyan
Verified answer
x*√(x²-x-2) ≥ 0
;
ОДЗ :x² -x -2 ≥ 0 ;
(x+1)(x-2) ≥ 0⇒ x∈[ -1 ;2] .
В области допустимых значении (ОДЗ) √(x² -x -2) ≥ 0 , позтому
x*√(x²-x-2) ≥ 0 ;если x≥0 .
-------- [-1 ] ///////// [2]-----------------
[0] ////////////////////////////////////
x ∈ {-1} U [0 ;2] .
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Answers & Comments
Verified answer
x*√(x²-x-2) ≥ 0 ;ОДЗ :x² -x -2 ≥ 0 ;
(x+1)(x-2) ≥ 0⇒ x∈[ -1 ;2] .
В области допустимых значении (ОДЗ) √(x² -x -2) ≥ 0 , позтому
x*√(x²-x-2) ≥ 0 ;если x≥0 .
-------- [-1 ] ///////// [2]-----------------
[0] ////////////////////////////////////
x ∈ {-1} U [0 ;2] .