Ответ:
1)cos3x=√3/2
3x=±arccos π\6+2πn
x=±π\18+2/3πn
2) cosx/4=-√2/2
x/4=±arccos 3π/4+2πn
x=±3π+8πn
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Ответ:
1)cos3x=√3/2
3x=±arccos π\6+2πn
x=±π\18+2/3πn
2) cosx/4=-√2/2
x/4=±arccos 3π/4+2πn
x=±3π+8πn