(3/4)^ (x^2) >= (4/3) ^ (2x-3)
(4/3)^(-x^2) >= (4/3)^(2x-3)
основание больше 1
без перемены знака снимаем основание
-x^2 >= 2x - 3
x^2 + 2x - 3 <= 0
D=4 + 12=16
x12=(-2+-4)/2 = - 3 1
(x + 3)(x - 1) <=0
++++++++++ [-3] --------------- [1] +++++++++
x∈[-3 1]
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(3/4)^ (x^2) >= (4/3) ^ (2x-3)
(4/3)^(-x^2) >= (4/3)^(2x-3)
основание больше 1
без перемены знака снимаем основание
-x^2 >= 2x - 3
x^2 + 2x - 3 <= 0
D=4 + 12=16
x12=(-2+-4)/2 = - 3 1
(x + 3)(x - 1) <=0
++++++++++ [-3] --------------- [1] +++++++++
x∈[-3 1]