October 2021 0 12 Report
Решите пож уравнения, я сама в алгебре полный ноль( a) x^3 - 2x^2 - x + 2 = 0
б) y^3 - y^2 = 16y - 16
в) 2y^2 - y^2 - 32^y + 16 = 0
г) 4x^3 - 3^2 = 4x - 3
Please enter comments
Please enter your name.
Please enter the correct email address.
You must agree before submitting.

Copyright © 2024 SCHOLAR.TIPS - All rights reserved.