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Scroll77
@Scroll77
July 2022
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Решите пожалуйста 10 класс
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sedinalana
Verified answer
1
a)tg30*sin60-cos0=1/√3*√3/2-1=1/2-1=-1/2
b)cosπ-sinπ/2+tg²π/3=-1-1+3=1
2
coaa<0 U tga<0⇒cosa/tga>0
3
sina=-√(1-cos²a)=-√(1-64/289)=-√(225/289)=-15/17
ctga=cosa/sina=8/17:(-15/17)=-8/17*17/15=-8/15
4
(1+sin²a)*ctg²a-1-ctg²a=ctg²a(1+sin²a-1)-1=ctg²a*sin²a-1=
=cos²a/sin²a &sin²a -1=cos²a-1=-sin²a
-----------------------------------
1/sin²a=1+ctg²a
5
sin²a+cos²a=1
7/10≠1
Ответ не существует
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Answers & Comments
Verified answer
1a)tg30*sin60-cos0=1/√3*√3/2-1=1/2-1=-1/2
b)cosπ-sinπ/2+tg²π/3=-1-1+3=1
2
coaa<0 U tga<0⇒cosa/tga>0
3
sina=-√(1-cos²a)=-√(1-64/289)=-√(225/289)=-15/17
ctga=cosa/sina=8/17:(-15/17)=-8/17*17/15=-8/15
4
(1+sin²a)*ctg²a-1-ctg²a=ctg²a(1+sin²a-1)-1=ctg²a*sin²a-1=
=cos²a/sin²a &sin²a -1=cos²a-1=-sin²a
-----------------------------------
1/sin²a=1+ctg²a
5
sin²a+cos²a=1
7/10≠1
Ответ не существует