Решите пожалуйста!!!!!!! 1)а² -b² -c²+2bc ----------------- b²-c²-a²-2ac 2) b4(с...

July 2022 1 1 Report

Решите пожалуйста!!!!!!!
1)а² -b² -c²+2bc
-----------------
b²-c²-a²-2ac
2) b4(степень)+4
--------------------
b²-2b+2
3)х(n+2 степень)-4х(n+1 степень)+4х(n степень)
----------------------------------------------
Х³-6х²+12х-8

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Удачник66

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Уже решал
1)
$\frac{a^2-b^2-c^2+2bc}{b^2-c^2-a^2-2ac} = \frac{a^2-(b-c)^2}{b^2-(c+a)^2}= \frac{(a-b+c)(a+b-c)}{(b-c-a)(b+c+a)}= \frac{-(b-a-c)(a+b-c)}{(b-a-c)(a+b+c)}=- \frac{a+b-c}{a+b+c}$

2)
$\frac{b^4+4}{b^2-2b+2}= \frac{b^4-2b^3+2b^2+2b^3-4b^2+4b+2b^2-4b+4}{b^2-2b+2}=$
$= \frac{(b^2-2b+2)(b^2+2b+2)}{b^2-2b+2} =b^2+2b+2$

3)
$\frac{x^{n+2}-4x^{n+1}+4x^n}{x^3-6x^2+12x-8}= \frac{x^n*(x^2-4x+4)}{x^3-3*2x^2+3*2^2x-2^3}= \frac{x^n*(x-2)^2}{(x-2)^3}= \frac{x^n}{x-2}$

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