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Ucheni4ok
@Ucheni4ok
August 2022
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Решите пожалуйста
1+x+|x^2-x-3|=0
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krugly1981
По определению модуля:
1 + x +x² - x - 3 =0 или 1 + x - x² + x + 3 =0
x² - 2 = 0 - x² + 2x + 4 = 0
x² = 2 x² - 2x - 4 =0
x = +/- √2 D = b² - 4ac = 4 - 4 ×(-4) = 4 + 16 = 20
x1,2 = 2+/-√20/2
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Answers & Comments
1 + x +x² - x - 3 =0 или 1 + x - x² + x + 3 =0
x² - 2 = 0 - x² + 2x + 4 = 0
x² = 2 x² - 2x - 4 =0
x = +/- √2 D = b² - 4ac = 4 - 4 ×(-4) = 4 + 16 = 20
x1,2 = 2+/-√20/2