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wtf234
@wtf234
December 2021
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Решите пожалуйста 2 задачу! В интернете ее нету можете не искать
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Verified answer
N=a*e^(-mgh/kT)
N=S*integral [0;беск] a*e^(-mgh/kT) dh = S*a*kT/mg
a=mgN/(S*kT)=b/кТ
n=b/кТ*e^(-mgh/kT)=b/кТ1*e^(-mgh1/kT1)
T1/Т=e^(mgh/kT-mgh1/kT1)
ln(T1/T)=mgh/kT-mgh1/kT1
mgh1/kT1=mgh/kT-ln(T1/T)
h1=hT1/T-ln(T1/T)*kT1/(mg)
h1=h
h(T1/T-1)=ln(T1/T)*kT1/(mg)
h=ln(T1/T)*kT1/(mg)/(T1/T-1)=ln(ню)*kT*/(mg(ню-1))- это ответ
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Answers & Comments
Verified answer
N=a*e^(-mgh/kT)N=S*integral [0;беск] a*e^(-mgh/kT) dh = S*a*kT/mg
a=mgN/(S*kT)=b/кТ
n=b/кТ*e^(-mgh/kT)=b/кТ1*e^(-mgh1/kT1)
T1/Т=e^(mgh/kT-mgh1/kT1)
ln(T1/T)=mgh/kT-mgh1/kT1
mgh1/kT1=mgh/kT-ln(T1/T)
h1=hT1/T-ln(T1/T)*kT1/(mg)
h1=h
h(T1/T-1)=ln(T1/T)*kT1/(mg)
h=ln(T1/T)*kT1/(mg)/(T1/T-1)=ln(ню)*kT*/(mg(ню-1))- это ответ