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паша12313
@паша12313
July 2022
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Решите пожалуйста
2x^{3}-11x^{2}+17х-6=0
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Санечка69
Verified answer
2x
³
- 11x
²
+ 17х - 6 = 0
2х
³ - 4х² + (-7х² + 14х) + (3х - 6) = 0
2х²(х - 2) -7х(х - 2) + 3(х - 2) = 0
(х - 2)(2х² - 7х + 3) = 0
х - 2 = 0 или 2х² - 7х + 3 = 0
х₁ = 2 D = (-7)² - 4 · 2 · 3 = 49 - 24 = 25; √25 = 5
х₂ = (7 - 5)/ (2 · 2) = 0,5
х₃ = (7 + 5)/(2 · 2) = 3
Ответ: 0,5; 2; 3.
2 votes
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Answers & Comments
Verified answer
2x³ - 11x² + 17х - 6 = 02х³ - 4х² + (-7х² + 14х) + (3х - 6) = 0
2х²(х - 2) -7х(х - 2) + 3(х - 2) = 0
(х - 2)(2х² - 7х + 3) = 0
х - 2 = 0 или 2х² - 7х + 3 = 0
х₁ = 2 D = (-7)² - 4 · 2 · 3 = 49 - 24 = 25; √25 = 5
х₂ = (7 - 5)/ (2 · 2) = 0,5
х₃ = (7 + 5)/(2 · 2) = 3
Ответ: 0,5; 2; 3.