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dimaalex607
@dimaalex607
December 2021
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решите пожалуйста 4 и 5
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mikael2
4. x(t)=t³-2t²+3t v(t)= x'(t)=3t²-4t+3 v(2)=12-8+3=7
5. f(x)=x²(x²-12x+36)=x⁴-12x³+36x²
f'(x)=4x³-36x²+72x=4x(x²-9x+18)=0
x1=0 x²-9x+18=0 x2=3 x3=6
-----------0-------------------3--------------------6-----------
- + - +
↓ x∈(-∞;0)∪(3;6) ↑ x∈(0;3)∪(6;∞) точки экстремума 0; 3; 6
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Answers & Comments
5. f(x)=x²(x²-12x+36)=x⁴-12x³+36x²
f'(x)=4x³-36x²+72x=4x(x²-9x+18)=0
x1=0 x²-9x+18=0 x2=3 x3=6
-----------0-------------------3--------------------6-----------
- + - +
↓ x∈(-∞;0)∪(3;6) ↑ x∈(0;3)∪(6;∞) точки экстремума 0; 3; 6