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jhonlock
@jhonlock
August 2021
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Решите пожалуйста ^5√96m^7n^-12, m>= 0, n>0
^4√625a^4b^5, a<0, b>=0
2.
2a^4√3a, a>0
расположите числа ^3√4, √3, 4^√5 в порядке возрастания
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jhonlock
April 2021 | 0 Ответы
esli komu ne trudno reshite pozhalujsta hotya by 1 2 zadaniya
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