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nahodkaalenka
@nahodkaalenka
August 2022
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решите пожалуйста 7-8 задание
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Бичора
Номер 7.
Ответ: -1.
Номер 8.
x^2-2x-3 ≤0
x^2-2x-3=0
По теореме Виета :
х1=-1
х2=3
[-1;3]
Ответ: 1.
1 votes
Thanks 1
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Answers & Comments
Ответ: -1.
Номер 8.
x^2-2x-3 ≤0
x^2-2x-3=0
По теореме Виета :
х1=-1
х2=3
[-1;3]
Ответ: 1.