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bocharnikovaliza
@bocharnikovaliza
August 2021
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Решите пожалуйста А1,А2,А3
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oganesbagoyan
Verified answer
A1.
∛(27*48) -∛(108*12) +2∛6 =∛((3³)*8*6) -∛(36*3)*2*6 +2∛6 =
=∛(3³*2³*6) - √(6³*6) +2∛6 =3*2∛6 -6∛6 +2∛6 =6∛6 - 6∛6 +2∛6 =
2∛6.
ответ
: 4 .
*****************************************************************************************************
A2.
(3^(2/3))^6*2^(-4)/(3^(-2))= 3^(2/3*6)*2^(-4)*3² =3^4* 3² *(1/2^4) =(3^6)/(2^4)=
=
729/16.
ответ
: 3 .
*****************************************************************************************************
A3.
(0,2)^(Loq(_0,2) ( 8+Loq(_5) 1/25 =(0,2)^(Loq(_0,2) 8*(0,2)^Loq(_5) 1/25 =
=8*(1/5)^(-2) =8*((5^(-1))^(-2) =8* 5^((-1)*(-2)) =8*5² =8*25 =
200.
ответ
: 1 .
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Answers & Comments
Verified answer
A1. ∛(27*48) -∛(108*12) +2∛6 =∛((3³)*8*6) -∛(36*3)*2*6 +2∛6 ==∛(3³*2³*6) - √(6³*6) +2∛6 =3*2∛6 -6∛6 +2∛6 =6∛6 - 6∛6 +2∛6 =2∛6.
ответ: 4 .
*****************************************************************************************************
A2. (3^(2/3))^6*2^(-4)/(3^(-2))= 3^(2/3*6)*2^(-4)*3² =3^4* 3² *(1/2^4) =(3^6)/(2^4)=
=729/16.
ответ: 3 .
*****************************************************************************************************
A3. (0,2)^(Loq(_0,2) ( 8+Loq(_5) 1/25 =(0,2)^(Loq(_0,2) 8*(0,2)^Loq(_5) 1/25 =
=8*(1/5)^(-2) =8*((5^(-1))^(-2) =8* 5^((-1)*(-2)) =8*5² =8*25 =200.
ответ: 1 .