Решите пожалуйста ._.
(a+2)³
(b-4)³
(a+2)³ = a^3+3a^2*2+3a*2^2+2^3=a^3+6a^2+12a+8
(b-4)³ = b^3-3b^2*4+3b*4^2-4^3=b^3-12b^2+48b-64
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(a+2)³ = a^3+3a^2*2+3a*2^2+2^3=a^3+6a^2+12a+8
(b-4)³ = b^3-3b^2*4+3b*4^2-4^3=b^3-12b^2+48b-64