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alasadi1107
@alasadi1107
August 2022
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nKrynka
Решение
1) y` = 10^x*ln10*sinx + 10^x*cosx
y`(0) = 10°ln10sin0 + 10°cos0 = 1
2) y = e^2x
y` = 2*(e^2x)
y`(0) = 2*e^2*0) = 2
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Answers & Comments
1) y` = 10^x*ln10*sinx + 10^x*cosx
y`(0) = 10°ln10sin0 + 10°cos0 = 1
2) y = e^2x
y` = 2*(e^2x)
y`(0) = 2*e^2*0) = 2