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надя325
@надя325
October 2021
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решите пожалуйста !Буду очень благодарна !
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математик2011
S = 2πRh
R = a*b*c/4S
S = a*b*sinC/2
S = 6*6*sin120/2 = (36*√3/2)/2 = 9√3
с² = a²+b² - 2abcos120 = 36+36 - 2*36*(-1/2) = 72 +36 = 108
c =√108 = 6√3
R = 6*6*6√3/4*9√3 = 6
S =2π*6*10 = 120π
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надя325
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Answers & Comments
R = a*b*c/4S
S = a*b*sinC/2
S = 6*6*sin120/2 = (36*√3/2)/2 = 9√3
с² = a²+b² - 2abcos120 = 36+36 - 2*36*(-1/2) = 72 +36 = 108
c =√108 = 6√3
R = 6*6*6√3/4*9√3 = 6
S =2π*6*10 = 120π