x^2-2x=t
t^2-3=2t
t^2-2t-3=0
D=4=12=16
t1=(2+4)/2=3; x^2-2x=3; x^2-2x-3=0;D=4=12=16;x1=(2+4)/2=3;x2=(2-4)/2=-1
t2=(2-4)/2=-1;x^2-2t+1=(x-1)^2=0;x3=1
Ответ x={-1;1;3}
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x^2-2x=t
t^2-3=2t
t^2-2t-3=0
D=4=12=16
t1=(2+4)/2=3; x^2-2x=3; x^2-2x-3=0;D=4=12=16;x1=(2+4)/2=3;x2=(2-4)/2=-1
t2=(2-4)/2=-1;x^2-2t+1=(x-1)^2=0;x3=1
Ответ x={-1;1;3}