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JuliaVoll10
@JuliaVoll10
August 2022
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Решите пожалуйста ,что сможете
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nKrynka
Решение
2) √2sinπ/8 * cosπ/8 = (√/2/2 ) * (2sinπ/8 * cosπ/8) = √2/2 * sunπ/4 =
= √2/2 *
√2/2 = 1/2
5) 8*(sin
π/12cosπ/12 - 1) = 8*[(1/2)*2sin
π/12cosπ/12 - 1] =
=
8*[(1/2)*siπ/6 - 1] = 8*(1/2 * 1/2 - 1) = 8*(- 3/4) = - 6
9) 8 * sin75°cos75° = 4*(2
sin75°cos75°) = 4*sin150
° =
= 4sin(180° - 30°) = 4sin30° = 4*(1/2) = 2
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Answers & Comments
2) √2sinπ/8 * cosπ/8 = (√/2/2 ) * (2sinπ/8 * cosπ/8) = √2/2 * sunπ/4 =
= √2/2 * √2/2 = 1/2
5) 8*(sinπ/12cosπ/12 - 1) = 8*[(1/2)*2sinπ/12cosπ/12 - 1] =
= 8*[(1/2)*siπ/6 - 1] = 8*(1/2 * 1/2 - 1) = 8*(- 3/4) = - 6
9) 8 * sin75°cos75° = 4*(2sin75°cos75°) = 4*sin150° =
= 4sin(180° - 30°) = 4sin30° = 4*(1/2) = 2