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Adilhanlox
@Adilhanlox
July 2022
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Решите пожалуйста
Докажите что ABCD прямоуг0льник
A(-3,-1) B(1;-1) C(1;-3) D(-3, -3)
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армения20171
АВ=(4;0);ВС=(0;-2)
cosB=(4•0+0•(-2))/(4•2)=0
<B=90°
cosa=(x1y1+x2y2)/√(x1²+y1²)•√(x2²+y2²)
AB=(4;0);AD=(0;-2)
cosA=(AB•AD)/|AB|•|AD|=
(4*0+0*(-2))/√4²*√(-2)²=0
<A=90°
DC=(-4;0);DA=(0;-2)
cosD=DC•DA/|DC|•DA|=
(-4•0+0•(-2)/√4²•√(-2)²=0
<D=90°
cosC=CB•CD/|CB|•|CD|=
(0*(-4)+0*(-2)/√4²•√(-2)²=0
<C=90°
|AB|=|CD|=√4²=4
|BC|=|AD|=√2²=2
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Answers & Comments
cosB=(4•0+0•(-2))/(4•2)=0
<B=90°
cosa=(x1y1+x2y2)/√(x1²+y1²)•√(x2²+y2²)
AB=(4;0);AD=(0;-2)
cosA=(AB•AD)/|AB|•|AD|=
(4*0+0*(-2))/√4²*√(-2)²=0
<A=90°
DC=(-4;0);DA=(0;-2)
cosD=DC•DA/|DC|•DA|=
(-4•0+0•(-2)/√4²•√(-2)²=0
<D=90°
cosC=CB•CD/|CB|•|CD|=
(0*(-4)+0*(-2)/√4²•√(-2)²=0
<C=90°
|AB|=|CD|=√4²=4
|BC|=|AD|=√2²=2