Решите пожалуйста. Мне нужно подробно. 1) 6^㏒ 36^81= 2)5^㏒ 25^26= 3)2^㏒ 0,5³=. Created by egor879. algebra-ru

Решите пожалуйста. Мне нужно подробно. 1) 6^㏒ 36^81= 2)5^㏒ 25^26= 3)2^㏒ 0,5³=...

July 2022 1 1 Report

Решите пожалуйста. Мне нужно подробно.
1) 6^㏒ 36^81=
2)5^㏒ 25^26=
3)2^㏒ 0,5³=

Answers & Comments

ЕкарныйБабай 6^(log₃₆ 81)=6^(log₆² 9²)=6^(log₆ 9)=9
5^(log₂₅ 36)=5^(log₅² 6²)=5^(log₅ 6)=6
2^(log₀₅ 3)= 2^(-1*log₂ 3)=2^(log₂ 1/3)=1/3 (0.5=1/2=2^(-1))

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