1) 912(10) = 1110010000(2) = 1620(8) = 390(16)
2) 10011100(2) = 156(10)
3) 30F(16) = 783(10)
4) 322(8) = 210(10) следовательно 322(8) < 232(10)
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Answers & Comments
1) 912(10) = 1110010000(2) = 1620(8) = 390(16)
2) 10011100(2) = 156(10)
3) 30F(16) = 783(10)
4) 322(8) = 210(10) следовательно 322(8) < 232(10)