Решите пожалуйста, надо продеференцировать функцию. Created by nubsaibot2017. matematika-ru

Решите пожалуйста, надо продеференцировать функцию...

nubsaibot2017 @nubsaibot2017

October 2021 1 15 Report

Решите пожалуйста, надо продеференцировать функцию

Answers & Comments

Miroslava227

Ответ:

$y = \sqrt[5]{7 {x}^{2} - 3x + 5} - \frac{5}{ {(x - 1)}^{3} } = \\ = {(7 {x}^{2} - 3x + 5) }^{ \frac{1}{5} } - 5 {(x - 1)}^{ - 3}$

$y' = \frac{1}{5} {(7 {x}^{2} - 3x + 5)}^{ - \frac{4}{5} } \times (7 {x}^{2} - 3x + 5)' - 5\times ( - 3) {(x - 1)}^{ - 4} = \\ = \frac{14x - 3}{5 \sqrt[5]{ {(7 {x}^{2} - 3x + 5)}^{4} } } + \frac{15}{ {(x - 1)}^{4} }$

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