а)5x²-17x-12>0
5x²-17x-12=0
D=289-4×5×(-12)=529=23²
x=17±23/10
x1=17+23/10=30/10=3
x2=17-23/10=-6/10=-0,6
(-∞;-0,6)U(3;+∞)
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а)5x²-17x-12>0
5x²-17x-12=0
D=289-4×5×(-12)=529=23²
x=17±23/10
x1=17+23/10=30/10=3
x2=17-23/10=-6/10=-0,6
(-∞;-0,6)U(3;+∞)