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tea74
@tea74
August 2021
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Решите пожалуйста номер 2 В.
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oganesbagoyan
Verified answer
2 в)
√((x²-6x)(x²+2)) / (x²+x) = √(x(x-6)(x²+2)) / x(
x+1)
x²+2
≥2 .
{
x(x-6) ≥ 0 ; x(x+1)≠0 ⇔{ x∈(-∞; 0] ∪ [6 ; ∞) ; x ≠ -1 ; x ≠0 .⇒
x∈(-∞; -1) ∪ (-1;0) U
[6 ; ∞)
.
ответ :
x∈(-∞; -1) ∪ (-1;0) U [6 ; ∞) .
P.S.
+ + - +
/////// (-1)///////// (0)----------- [6]///////////.
Удачи донор !
2 votes
Thanks 1
tea74
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Answers & Comments
Verified answer
2 в)√((x²-6x)(x²+2)) / (x²+x) = √(x(x-6)(x²+2)) / x(x+1)
x²+2 ≥2 .
{ x(x-6) ≥ 0 ; x(x+1)≠0 ⇔{ x∈(-∞; 0] ∪ [6 ; ∞) ; x ≠ -1 ; x ≠0 .⇒
x∈(-∞; -1) ∪ (-1;0) U [6 ; ∞) .
ответ : x∈(-∞; -1) ∪ (-1;0) U [6 ; ∞) .
P.S.
+ + - +
/////// (-1)///////// (0)----------- [6]///////////.
Удачи донор !