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mikro2003
@mikro2003
July 2021
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Решите пожалуйста номер 4
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Hembek
Д=√25-4*3*1=√25-12=√13
х1=(5-√13)/2
х2=(5+√13)/2
х1=(5-√13)/2+3=(11-√13)/2
х2=(11+√13)/2
х1+х2=-п
-п=11
х1*х2=q
q=(121-13)/4=27
уравнение⇒х²-11х+27
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Answers & Comments
х1=(5-√13)/2
х2=(5+√13)/2
х1=(5-√13)/2+3=(11-√13)/2
х2=(11+√13)/2
х1+х2=-п
-п=11
х1*х2=q
q=(121-13)/4=27
уравнение⇒х²-11х+27