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yanaboeva2003
@yanaboeva2003
July 2022
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Решите пожалуйста первый вариант☹️
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Koteileleyy
(х+3)^2=x^2+6x+9
(4a-1)^2=16a^2-8a+1
(4x-3y)^2=16x^2-24xy+9y^2
(a^4-2)^2=a^18-4a^4+4
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yanaboeva2003
А можешь и 2 и 3 номер сделать?
Koteileleyy
(x^2+4x+4)=(x+2)^2 (4x^2-28xy+49y^2)=(2x-7y)^2
Koteileleyy
(5a+4)^2-40a=25a^2+40a+16-40a=25a^2+16 16x^2-4(2x+3)^2=16x^2-16x^2-48x-36=-48x-36
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Answers & Comments
(4a-1)^2=16a^2-8a+1
(4x-3y)^2=16x^2-24xy+9y^2
(a^4-2)^2=a^18-4a^4+4