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nedenispolybomy
@nedenispolybomy
October 2021
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Решите пожалуйста, подробно. Во вложениях. Спасибо.
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oganesbagoyan
Verified answer
M₁(5; 1 ;4) , M₂(3 ; 2 ;5) xoz.
(x -x₁)/(x₂ -x₁) =(y -y₁)/*(y₂ -y₁) =(z-z₁)/(z₂ -z₁) .
(x - 5)/(3 -5) =(y-1)/(2 -1) =(z - 4)/(5-4) ;
x - 5)/(-2) =y-1 =z - 4 ;
на плоскости xoz y =0
x - 5)/(-2) = -1 =z - 4
⇒(x - 5)/(-2) = -1⇒x =7 ;
z - 4 = -1 ⇒ z =3 .
ответ:
A (7 ; 0 ; 3)
.
2 votes
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Answers & Comments
Verified answer
M₁(5; 1 ;4) , M₂(3 ; 2 ;5) xoz.(x -x₁)/(x₂ -x₁) =(y -y₁)/*(y₂ -y₁) =(z-z₁)/(z₂ -z₁) .
(x - 5)/(3 -5) =(y-1)/(2 -1) =(z - 4)/(5-4) ;
x - 5)/(-2) =y-1 =z - 4 ;
на плоскости xoz y =0
x - 5)/(-2) = -1 =z - 4
⇒(x - 5)/(-2) = -1⇒x =7 ;
z - 4 = -1 ⇒ z =3 .
ответ: A (7 ; 0 ; 3) .