Решите пожалуйста предел!!). Created by nellylovett26. matematika-ru

Решите пожалуйста предел!!)...

August 2021 2 2 Report

Решите пожалуйста предел!!)

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Lim[d(√(4-x)+√(x+12)/dx:d(x²+2x-8)/dx]=
=lim[(1/2√(4-x)+1/2√(x+12))/(2x+2)]=
=lim[(√(4-x)+√(x+12))/((4x+4)√(4-x)*√(x+12))]=
=lim[(1/√(4-x)*1/√(x+12)*(√(4-x)+√(x+12))/(4x+4)]=
=[1/√8*1/√8*(√8+√8)/(-16+4)]=[(2√8*1/8)/(-12)]=2/(-12√8)=-1/6√8=-1/12√2

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kirichekov

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Решение во вложении-----------------------

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