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Raskolnikov1
@Raskolnikov1
September 2021
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Решите пожалуйста пример
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nafanya2014
Verified answer
2х·(2х+3у)-(х+у)²=2х·2х+2х·3у-(х²+2ху+у²)=4х²+
6ху
-х²-
2ху
-у²=
=3х²+4ху-у².
1 votes
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Answers & Comments
Verified answer
2х·(2х+3у)-(х+у)²=2х·2х+2х·3у-(х²+2ху+у²)=4х²+6ху-х²-2ху-у²==3х²+4ху-у².