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Tatapapy
@Tatapapy
July 2022
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nKrynka
Решение
2x + y = 5
x² + y² = 25
y = 5 - 2x
x² + (5 - 2x)² = 25
x² + 25 - 20x + 4x² = 25
5x² - 20x = 0
5x*(x - 4) = 0
5x = 0
x₁ = 0
x - 4 = 0
x₂ = 4
x₁ = 0
y₁ = 5 - 2*0
y₁ = 5
(0; 5)
x₂ = 4
y₂ = 5 - 2*4
y₂ = - 3
(4; - 3)
Ответ: (0; 5) ;
(4; - 3)
2 votes
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Answers & Comments
2x + y = 5
x² + y² = 25
y = 5 - 2x
x² + (5 - 2x)² = 25
x² + 25 - 20x + 4x² = 25
5x² - 20x = 0
5x*(x - 4) = 0
5x = 0
x₁ = 0
x - 4 = 0
x₂ = 4
x₁ = 0
y₁ = 5 - 2*0
y₁ = 5
(0; 5)
x₂ = 4
y₂ = 5 - 2*4
y₂ = - 3
(4; - 3)
Ответ: (0; 5) ; (4; - 3)