Решите, пожалуйста СРОЧНО!!. Created by PettyScum. algebra-ru

Решите, пожалуйста СРОЧНО!!...

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1) a) (x²-20)/(x√5-10)=[(x-2√5)(x+2√5)]/[√5(x-2√5)]=(x+2√5)/√5=(x·√5+10)/5

б) [3a-2√(6ab)+2b]/[√(27a³)-√(8b³)]=
=[√(3a)-√(2b)]²/{[√(3a)-√(2b)]·[3a+√(6ab)+2b]}=[√(3a)-√(2b)]/{·[3a+√(6ab)+2b]}

2) a) 5/√(5-b)=5√(5-b)/(5-b)

б) (3+√a)/(√3-a)=(3+√a)²/(3-a²)

3)
[(5√a/√b)+1/√a]·[2√(ab)/(25a²-b)]=[(5a+√b)/√(ab)]·[2√(ab)/{(5a-√b)·(5a+√b)}]=
=2/(5a-√b)

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MizoriesKun Х²-(√20)² (х-2√5)(х+2√5) (х+2√5)
________ = _____________ = __________
х√5-(√10)²   √5(х-2√5√)   √5
_____________________________________________________________

3а-2√(6аb)+2b (√(3a)-√(2b))²
____________ = ____________________________ =
√27a³ -√8b³ (√(3a)-√(2b)(√(9a²)+√(6ab)+√(4b²)

  (√(3a)-√(2b)) (√(3a)-√(2b)
= __________________ =_______________
(√(9a²)+√(6ab)+√(4b²) ((3a)+√(6ab)+(2b)
______________________________________________________

5 5*√(5-b) 5*√(5-b)
_____ = ___________ = ___________
√(5-b) √(5-b)*√(5-b) 5-b
______________________________________________________________

√3 +a (√3 +a)(√3 +a) (√3 +a)²
______= _____________ = ______
√3-a (√3 -a)(√3 +a) 3-a²
________________________________________________________________

5√a 1 2√(ab) 5√a*√a+√b 2√(ab)
(____ + _____ ) * _________ = ___________ * _______ =
√b √a 25a²-b √(ab) 25a²-b

(5a+√b) * 2√(ab) 2
= _________________ = __________
  √(ab)*(5a-√b)(5a+√b) 5a-√b

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30 ballov srochno reshite pozhalujsta cepochku feoh2 feo fe

reshite pozhalujsta srochnoda2e157e147132a35f998142a1605bc8 42638

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