решите пожалуйста только подробно
√121-10√6.4*√0.1=
2√5-√45+√80=
=SQR121-10SQR(6.4*0.1)=11-10SQR(0.64)=11-10*0.8=10-8=2
=2sqr5-sqr(5*9)+sqr(5*16)=2sqr5-3sqr5+4sqr5=3sqr5
sqr=корень квадратный
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=SQR121-10SQR(6.4*0.1)=11-10SQR(0.64)=11-10*0.8=10-8=2
=2sqr5-sqr(5*9)+sqr(5*16)=2sqr5-3sqr5+4sqr5=3sqr5
sqr=корень квадратный