Home
О нас
Products
Services
Регистрация
Войти
Поиск
Kawaimi
@Kawaimi
August 2022
1
5
Report
Решите, пожалуйста, тригонометрические уравнения
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
oganesbagoyan
Verified answer
1)
cosπ(x+18)/24 =√2/2 ;
π(x+18)/24 =(+/-)π/4 +2πk ,k∈Z;
x+18 =(+/-)6 +48 k;
x₁= -18 -6 +48k; min(x₁>0)
=12
, при k=0.
x₂= -18 +6 +48k; min(x₂>0)=
36 ,
при к =1.
ответ :
12
.
2)
2(1+cos²πx/20) -3√2sinπx/20 =0;
2(2-sin²πx/20) -3√2sinπx/20 =0;
2sin²πx/20 -3√2sinπx/20 -4 =0;
обозначим t =sinπx/20 , | t | ≤ 1 , получим :
2t² -3√2t -4 =0;
D=(3√2)² -4*2(-4) =50 =(5√2)² ;
t₁= (3√2 -5√2)/4 = -√2/2;
t₂= (3√2 + 5√2)/4 = 2√2 >1 не решение
-----------------------------
sinπx/20= - √2/2 ;
πx₁/20 = -π/4 +2πk ⇒ x₁ = -5 +40k ⇒
πx₂/20 = π - π/4 +2πk ;x₂ = 15 +40k
1 votes
Thanks 2
More Questions From This User
See All
Kawaimi
August 2022 | 0 Ответы
reshite pozhalujsta uravneniyad6181e0289ced5db08e90e5ab684cb70 89654
Answer
Kawaimi
July 2022 | 0 Ответы
pomogite pozhalujsta reshit zadachki po geometrii bokovye storony ravnobedrenn
Answer
Kawaimi
July 2022 | 0 Ответы
pomogite reshit pozhalujsta zadaniya po algebrena pervom liste zadaniya 3 i 4na
Answer
Kawaimi
July 2022 | 0 Ответы
opishite egp centralnogo rajona rossii po planu polozhenie rajona na territorii
Answer
Kawaimi
July 2022 | 0 Ответы
vstavte propushennye slovawhen i look into your eyesi see colour seaso
Answer
Kawaimi
July 2022 | 0 Ответы
kakie idei epohi prosvesheniya otrazheny v deklaracii prav cheloveka i grazhdanina 17
Answer
Kawaimi
July 2022 | 0 Ответы
reshite pozhalujsta vtoroe i trete zadaniya
Answer
Kawaimi
October 2021 | 0 Ответы
pomogite pozhalujsta reshit zadachku po himii molodomu ogorodniku neobhodim
Answer
Kawaimi
September 2021 | 0 Ответы
napishite uravneniya sleduyushih reakcij i otvette na voprosy
Answer
Kawaimi
August 2021 | 0 Ответы
vychislite pozhalujsta sm vlozhenie
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "Решите, пожалуйста, тригонометрические уравнения..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
1) cosπ(x+18)/24 =√2/2 ;π(x+18)/24 =(+/-)π/4 +2πk ,k∈Z;
x+18 =(+/-)6 +48 k;
x₁= -18 -6 +48k; min(x₁>0) =12 , при k=0.
x₂= -18 +6 +48k; min(x₂>0)= 36 , при к =1.
ответ : 12.
2) 2(1+cos²πx/20) -3√2sinπx/20 =0;
2(2-sin²πx/20) -3√2sinπx/20 =0;
2sin²πx/20 -3√2sinπx/20 -4 =0;
обозначим t =sinπx/20 , | t | ≤ 1 , получим :
2t² -3√2t -4 =0;
D=(3√2)² -4*2(-4) =50 =(5√2)² ;
t₁= (3√2 -5√2)/4 = -√2/2;
t₂= (3√2 + 5√2)/4 = 2√2 >1 не решение
-----------------------------
sinπx/20= - √2/2 ;
πx₁/20 = -π/4 +2πk ⇒ x₁ = -5 +40k ⇒
πx₂/20 = π - π/4 +2πk ;x₂ = 15 +40k