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janabbb
@janabbb
August 2022
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Решите, пожалуйста, уравнение( 4 ^x)+ (2^ x+1 )= 80
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sedinalana
Verified answer
4^x+2*2^x-80=0
2^x=a
a²+2a-80=0
a1+a2=-2 U a1*a2=-80
a1=-10⇒2^x=-10 нет решения
a2=8⇒2^x=8⇒x=3
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Answers & Comments
Verified answer
4^x+2*2^x-80=02^x=a
a²+2a-80=0
a1+a2=-2 U a1*a2=-80
a1=-10⇒2^x=-10 нет решения
a2=8⇒2^x=8⇒x=3