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lekonsta
@lekonsta
August 2022
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Решите, пожалуйста, уравнение:
cos3x+cosx=0
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DariosI
Verified answer
Cos3x+cosx=0
2cos(3x+x)/2*cos(3x-x)/2=0
2cos2x*cosx=0
cosx=0
x=π/2+πn, n∈Z
cos2x=0
2x=π/2+πn, n∈Z
x=π/4+πn/2, n∈Z
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Answers & Comments
Verified answer
Cos3x+cosx=02cos(3x+x)/2*cos(3x-x)/2=0
2cos2x*cosx=0
cosx=0
x=π/2+πn, n∈Z
cos2x=0
2x=π/2+πn, n∈Z
x=π/4+πn/2, n∈Z