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KsenyaCollins
@KsenyaCollins
August 2022
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решите пожалуйста уравнение -x^2+2x+3=0
срочно
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666Наська666
-x^2+2x+3=0 |:(-1)
x^2-2x-3=0
D=(-2)^2-4*1*(-3)=4+12=16(4)
x1,2=(2+-4)/2
x1=3
x2=-1
1 votes
Thanks 1
Dana315
-x^2+2x+3=0 (:-1)
X^2-2x-3=0
По теореме виетта
Х1+х2=2
Х1*х2=-3
Х1=1
Х2=3
0 votes
Thanks 0
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Answers & Comments
x^2-2x-3=0
D=(-2)^2-4*1*(-3)=4+12=16(4)
x1,2=(2+-4)/2
x1=3
x2=-1
X^2-2x-3=0
По теореме виетта
Х1+х2=2
Х1*х2=-3
Х1=1
Х2=3