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danil2501diukin
@danil2501diukin
December 2021
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Donaticher
А) 100a^2 - 20a + 1 = (10a - 1)^2
б) 81x^2 - 25y^2 = (9x - 5y)*(9x+5y)
в) 27x^3 - 125y^3 =(3x - 5y) * (9x^2 + 15xy + 25y^2)
г) (x^4 - x^3) - (x-1) = x^3 (x-1) - 1(x-1) = (x^3 - 1) *(x - 1)
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Donaticher
Отметь как лучшее :)
danil2501diukin
Спасибо!"
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Answers & Comments
б) 81x^2 - 25y^2 = (9x - 5y)*(9x+5y)
в) 27x^3 - 125y^3 =(3x - 5y) * (9x^2 + 15xy + 25y^2)
г) (x^4 - x^3) - (x-1) = x^3 (x-1) - 1(x-1) = (x^3 - 1) *(x - 1)