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НяШеЧкА2090
@НяШеЧкА2090
August 2022
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mmb1
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А. (1 - sin 45)/ (1 - cos45) = (1 - √2/2)/(1 - √2/2) = 1
б. не видно
д. |√18 - √32| /(√2 + √50) = (√(16*2) - √(9*2))/(√2 + √25*2) = (4√2 - 3√2)/ (√2 + 5√2) = √2/6√2 = 1/6
в. √(3 + √(5 - √(13 + √48)))
делаем по частям
√(13 + √48) = √(12 + 2√12*1 + 1) = √(√12² + 2√12*1 + 1) = √(√12 + 1)² = √12 + 1
√(5 - √(13 + √48)) = √(5 - √12 - 1) = √( 3 - 2√3*1 + 1) = √(√3 - 1)² = √3 - 1
√(3 + √(5 - √(13 + √48))) = √(3 + √3 - 1) = √(2+√3)
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Answers & Comments
Verified answer
А. (1 - sin 45)/ (1 - cos45) = (1 - √2/2)/(1 - √2/2) = 1б. не видно
д. |√18 - √32| /(√2 + √50) = (√(16*2) - √(9*2))/(√2 + √25*2) = (4√2 - 3√2)/ (√2 + 5√2) = √2/6√2 = 1/6
в. √(3 + √(5 - √(13 + √48)))
делаем по частям
√(13 + √48) = √(12 + 2√12*1 + 1) = √(√12² + 2√12*1 + 1) = √(√12 + 1)² = √12 + 1
√(5 - √(13 + √48)) = √(5 - √12 - 1) = √( 3 - 2√3*1 + 1) = √(√3 - 1)² = √3 - 1
√(3 + √(5 - √(13 + √48))) = √(3 + √3 - 1) = √(2+√3)