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frozenolaf1
@frozenolaf1
October 2021
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решите пожалуйста весь номер 55 и весь номер 59
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manyny06
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59.а. 2√3+7√3-√2=9√3-√2
б.√(4*5)-√(25*3)+√(16*3)=2√5-5√3+4√3 = 2√5-√3
в. √(16*2)+√(25*2)-√(9*2) = 4√2+5√2-3√2 = 6√2
г.2√(9*3)-3√(25*3) -√10= 6√3-15√3-√10 = -9√3-√10
д.1\2 √(100*2) - √(81*2) - 7 = 1\2*10√2- 9√2 - 7= 5√2-9√2-7= -4√2-7
е. 4*3 -1\9√(9*7) +3\4√(16*7) = 12 - 1\9*3√7+3\4*4√7 = 12-1\3 √7+ 3√7 =12 - 2 2\3√7
55.а. √(108* 1\81) = √(12\9)=√(4\3)
б.√(180*0.01) = √(1.8)
в. -√(128 * 9\64) = -√18
г. 1.25 = 1 1\4 = 5\4, √(320* 25\16 = √(20*25) = √500
д. 0.02 = 1\50 . √(300 * 1\2500) = √(3\25)
е.0.05 = 5\100 = 1\20, √(175*1\400) = √(7\8)
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59.а. 2√3+7√3-√2=9√3-√2б.√(4*5)-√(25*3)+√(16*3)=2√5-5√3+4√3 = 2√5-√3
в. √(16*2)+√(25*2)-√(9*2) = 4√2+5√2-3√2 = 6√2
г.2√(9*3)-3√(25*3) -√10= 6√3-15√3-√10 = -9√3-√10
д.1\2 √(100*2) - √(81*2) - 7 = 1\2*10√2- 9√2 - 7= 5√2-9√2-7= -4√2-7
е. 4*3 -1\9√(9*7) +3\4√(16*7) = 12 - 1\9*3√7+3\4*4√7 = 12-1\3 √7+ 3√7 =12 - 2 2\3√7
55.а. √(108* 1\81) = √(12\9)=√(4\3)
б.√(180*0.01) = √(1.8)
в. -√(128 * 9\64) = -√18
г. 1.25 = 1 1\4 = 5\4, √(320* 25\16 = √(20*25) = √500
д. 0.02 = 1\50 . √(300 * 1\2500) = √(3\25)
е.0.05 = 5\100 = 1\20, √(175*1\400) = √(7\8)