решите пожалуйста во вложении. Created by Zalesova. matematika-ru

12:(√a/b +1)=2:(√a+b)/2=2b/(√a+b)[(a√a+b³)-√ab*(√a+b))*(a-b²)(√a+b)=[(√a+b)(a-√ab+b²)-√ab(√a+b)/(a-b²)(√a+b)==(√a+b)(a-√ab+b²-√ab)/(a-b²)(√a+b)=(√a-b)²/(√a-b)(√a+b)=(√a-b)/(√a+b)получили2b/(√a+b)+(√a-b)/(√a+b)=(2b+√a-b)/(√a+b)=(b+√a)/(√a+n)=1Ответ 22ОДЗ{x>0lgx-lg2≠0⇒lgx≠lg2⇒x≠22*lg(x/3)=lg(x/2)lg(x²/9)=lg(x/2)x²/9=x/22x²=9x2x²-9x=0x(2x-9)=0x=0∉ОДЗ2x-9=02x=9x=4,5Ответ 43ОДЗ(x-√7)(x+√7)≥0x≤-√7 U x=√7x∈(-∞;-√7] U [√7;∞)√(x²+9)=2+√(x²-7)возведем в квадратx²+9=4+4√(x²-7)+x²-74√(x²-7)=12√(x²-7)=3возведем в квадратx²-7=9x²=16x=-4 U x=4-4+4=0Ответ 3park01park01Смотри во вложении.спасибо, могу я вам ещё примеры скинуть?Давайтекак мне вам скинуть?в третьем ошибка со знаками напутали. и нет ответа на вопрос. И большая просьба не отвечайте на большое количество заданийпочему не отвечать? Новые вопросы в МатематикаРасстояние от Земли до Луны 3,8⋅10^5 км. Искусственный спутник Земли лежит на прямой между Землей и Луной, в два раза дальше от Луны, чем от Земли. Ра…сстояние от искусственного спутника до Земли ___км.ДАМ 25 БАЛЛОВ. 8 номернайти координаты и длину вектороа *Довжина середньої лінії трапеції дорівнює 5 см, а довжина відрізка, якийз'єднує середини основ, - 3 см. Кути при більшій основі дорівнюють 300 і600.…Знайдіть основи трапеції.7. Упростите выражение (x²+2x+4). (x-2)-3(2x-3)- (2x + 3) =Помогите пожалуйста только быстро Если, ABCD-трапеция, ВD - биссектриса. угол ADC = 110° и AB = BD, то сравните: угол С и 110 градусов60% всех пассажиров самолета знают английский, а 48% немецкий и 25% знающих немецкий и английский. Сколько процентов пассажиров не знает ни английског…о, ни немецкого?Сравните х и 15, если:В первой коробке есть 2 красных и 4 желтых шара, а во второй коробке 3 красных и 2 желтых шара. Ученик не глядя взял один шар из первой коробки и поло…жил во вторую коробку. Какова вероятность того, что взятый наугад шар из второй коробки окажется красным.ПредыдущийСледующийВместе мы знаем большеЭтот сайт использует cookies Политика Cookies . 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(x-2)-3(2x-3)- (2x + 3) =\u200b"},{"id":49787629,"content":"\u041f\u043e\u043c\u043e\u0433\u0438\u0442\u0435 \u043f\u043e\u0436\u0430\u043b\u0443\u0439\u0441\u0442\u0430 \u0442\u043e\u043b\u044c\u043a\u043e \u0431\u044b\u0441\u0442\u0440\u043e \u200b"},{"id":49787625,"content":"\u0415\u0441\u043b\u0438, ABCD-\u0442\u0440\u0430\u043f\u0435\u0446\u0438\u044f, \u0412D - \u0431\u0438\u0441\u0441\u0435\u043a\u0442\u0440\u0438\u0441\u0430. \u0443\u0433\u043e\u043b ADC = 110\u00b0 \u0438 AB = BD, \u0442\u043e \u0441\u0440\u0430\u0432\u043d\u0438\u0442\u0435: \u0443\u0433\u043e\u043b \u0421 \u0438 110 \u0433\u0440\u0430\u0434\u0443\u0441\u043e\u0432\u200b"},{"id":49787622,"content":"60% \u0432\u0441\u0435\u0445 \u043f\u0430\u0441\u0441\u0430\u0436\u0438\u0440\u043e\u0432 \u0441\u0430\u043c\u043e\u043b\u0435\u0442\u0430 \u0437\u043d\u0430\u044e\u0442 \u0430\u043d\u0433\u043b\u0438\u0439\u0441\u043a\u0438\u0439, \u0430 48% \u043d\u0435\u043c\u0435\u0446\u043a\u0438\u0439 \u0438 25% \u0437\u043d\u0430\u044e\u0449\u0438\u0445 \u043d\u0435\u043c\u0435\u0446\u043a\u0438\u0439 \u0438 \u0430\u043d\u0433\u043b\u0438\u0439\u0441\u043a\u0438\u0439. \u0421\u043a\u043e\u043b\u044c\u043a\u043e \u043f\u0440\u043e\u0446\u0435\u043d\u0442\u043e\u0432 \u043f\u0430\u0441\u0441\u0430\u0436\u0438\u0440\u043e\u0432 \u043d\u0435 \u0437\u043d\u0430\u0435\u0442 \u043d\u0438 \u0430\u043d\u0433\u043b\u0438\u0439\u0441\u043a\u043e\u0433\u043e, \u043d\u0438 \u043d\u0435\u043c\u0435\u0446\u043a\u043e\u0433\u043e?\u200b"},{"id":49787619,"content":"\u0421\u0440\u0430\u0432\u043d\u0438\u0442\u0435 \u0445 \u0438 15, \u0435\u0441\u043b\u0438:\u200b"},{"id":49787618,"content":"\u0412 \u043f\u0435\u0440\u0432\u043e\u0439 \u043a\u043e\u0440\u043e\u0431\u043a\u0435 \u0435\u0441\u0442\u044c 2 \u043a\u0440\u0430\u0441\u043d\u044b\u0445 \u0438 4 \u0436\u0435\u043b\u0442\u044b\u0445 \u0448\u0430\u0440\u0430, \u0430 \u0432\u043e \u0432\u0442\u043e\u0440\u043e\u0439 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решите пожалуйста во вложении...

Zalesova @Zalesova

August 2022 1 19 Report

решите пожалуйста во вложении

Answers & Comments

park01 1
2:(√a/b +1)=2:(√a+b)/2=2b/(√a+b)

[(a√a+b³)-√ab*(√a+b))*(a-b²)(√a+b)=[(√a+b)(a-√ab+b²)-√ab(√a+b)/(a-b²)(√a+b)=
=(√a+b)(a-√ab+b²-√ab)/(a-b²)(√a+b)=(√a-b)²/(√a-b)(√a+b)=(√a-b)/(√a+b)
получили
2b/(√a+b)+(√a-b)/(√a+b)=(2b+√a-b)/(√a+b)=(b+√a)/(√a+n)=1
Ответ 2
2
ОДЗ
{x>0
lgx-lg2≠0⇒lgx≠lg2⇒x≠2
2*lg(x/3)=lg(x/2)
lg(x²/9)=lg(x/2)
x²/9=x/2
2x²=9x
2x²-9x=0
x(2x-9)=0
x=0∉ОДЗ
2x-9=0
2x=9
x=4,5
Ответ 4
3
ОДЗ
(x-√7)(x+√7)≥0
x≤-√7 U x=√7
x∈(-∞;-√7] U [√7;∞)
√(x²+9)=2+√(x²-7)
возведем в квадрат
x²+9=4+4√(x²-7)+x²-7
4√(x²-7)=12
√(x²-7)=3
возведем в квадрат
x²-7=9
x²=16
x=-4 U x=4
-4+4=0
Ответ 3

park01park01

Смотри во вложении.

спасибо, могу я вам ещё примеры скинуть?
Давайте
как мне вам скинуть?
в третьем ошибка со знаками напутали. и нет ответа на вопрос. И большая просьба не отвечайте на большое количество заданий
почему не отвечать?