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vika170420
@vika170420
July 2022
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Решите пожалуйста (x^2-4)^2+x^2-4=0
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volochkos
X^4-8x^2+16+x^2-4=0
x^4-7x^2+12=0
x^2=y
y^2-7y+12=0
D=(-7)^2-12*4=49-48=1
y1=(7-1)/2=6/2=3
y2=(7+1)/2=8/2=4
x1=корень из 3 x2=-корень из 3
x3=2 x4=-2
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Answers & Comments
x^4-7x^2+12=0
x^2=y
y^2-7y+12=0
D=(-7)^2-12*4=49-48=1
y1=(7-1)/2=6/2=3
y2=(7+1)/2=8/2=4
x1=корень из 3 x2=-корень из 3
x3=2 x4=-2