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Stas9999
@Stas9999
August 2021
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Решите пожалуйста
X^2+2x-3>или равно 0
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KarinaYouchi
X^2+2x-3≥0
x^2+2x-3=0
x1*x2=-3
x1+x2=-2
x1=1
x2=-3
(x-1)(x+3)≥0
+ - +
/////////////// //////////////
------------[-3]--------------------------[1]--------------
Ответ: (-∞;-3] U[1;+∞)
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Thanks 1
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Answers & Comments
x^2+2x-3=0
x1*x2=-3
x1+x2=-2
x1=1
x2=-3
(x-1)(x+3)≥0
+ - +
/////////////// //////////////
------------[-3]--------------------------[1]--------------
Ответ: (-∞;-3] U[1;+∞)