1) S=12 , AA1=2
S=0,5*BC*2=12 , BC=12:(2*0,5)=12
2) S=4,5 , BC=3
S=0,5*AC*BC , 4,5=0,5*AC*3 , AC=3
AB= √(AC²+BC²)=√(9+9)=3√2
S=0,5*CC1*AB ⇒ 4,5=0,5*CC1*3 , CC1=3
3) AC=10 , AB=8
BC=√(AC²-AB²)=√(100-64)=6
S=0,5*AB*BC=0,5*8*6=24
S=0,5*AC*BB1 ⇒ 24=0,5*10*BB1 , BB1=4,8
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Verified answer
1) S=12 , AA1=2
S=0,5*BC*2=12 , BC=12:(2*0,5)=12
2) S=4,5 , BC=3
S=0,5*AC*BC , 4,5=0,5*AC*3 , AC=3
AB= √(AC²+BC²)=√(9+9)=3√2
S=0,5*CC1*AB ⇒ 4,5=0,5*CC1*3 , CC1=3
3) AC=10 , AB=8
BC=√(AC²-AB²)=√(100-64)=6
S=0,5*AB*BC=0,5*8*6=24
S=0,5*AC*BB1 ⇒ 24=0,5*10*BB1 , BB1=4,8