1. дано V(CH4) = 100 L ---------------------- V(O2)-? 100 X CH4+2O2-->CO2+2H2O 1mol 2mol X = 100*2 / 1 = 200 L ответ 200 л 2. дано m(Pb) = 41.4 g ------------------------- V(H2)-? X 41.4 PbO2+2H2-->Pb+2H2O M(Pb) = 207 g/mol Vm = 22.4 L/mol 2*22.4 207 X = 44.8*41.4 / 207 = 8.96 L ответ 8.96 л
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1. даноV(CH4) = 100 L
----------------------
V(O2)-?
100 X
CH4+2O2-->CO2+2H2O
1mol 2mol
X = 100*2 / 1 = 200 L
ответ 200 л
2.
дано
m(Pb) = 41.4 g
-------------------------
V(H2)-?
X 41.4
PbO2+2H2-->Pb+2H2O M(Pb) = 207 g/mol Vm = 22.4 L/mol
2*22.4 207
X = 44.8*41.4 / 207 = 8.96 L
ответ 8.96 л