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December 2021
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Решите пожалуйста задачу 1 и 3,очень срочно!
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1. По т Пифагора найдем KN;
KN=√(MN²-MK²)=√(26²-10²)=√(676-100)=√576=24
найдем S тр=KN*MK/2=24*10/2=120
Отсюда найдем КТ=2Sтр/MN=240/26=120/13=9 целых 3/13.
3.KN=√(EK²+EN²)=√(6²+8²)=√(36+64)=√100=10
MN=KN²/NE=10²/8=100/8=12.5
MK=√(MN²-KN²)=√(12.5²-10²)=√(156.25-100)=√56.25=7.5
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Answers & Comments
KN=√(MN²-MK²)=√(26²-10²)=√(676-100)=√576=24
найдем S тр=KN*MK/2=24*10/2=120
Отсюда найдем КТ=2Sтр/MN=240/26=120/13=9 целых 3/13.
3.KN=√(EK²+EN²)=√(6²+8²)=√(36+64)=√100=10
MN=KN²/NE=10²/8=100/8=12.5
MK=√(MN²-KN²)=√(12.5²-10²)=√(156.25-100)=√56.25=7.5