0,2*10*√3+8/4√3+4√3=8√3;
(2√5+1)(√45-2)= 6*5+3√5-4√5-2=28-√5;
(2+√5)^2-(√5-3)^2=4+4√5+5-(5-6√5+9)=10√5-5=5*(√5-1);
2.
(√14-7)/(2-√14)=√7(√2-√7)/(√2(√2-√7))=√7/√2=√3,5;
(√3)^3-(√a)^3/((-1)(√3-√a))= (√3-√a)*(3-√3a+a)/((-1)(√3-√a))= √3a-3-a.
3
5*(2√2+√3)/((2√2-√3)((2√2+√3))=5*(2√2+√3)/(4*2-3)=2√2+√3;
(x-1)/(√(x+3)-2)=(x-1)(√(x+3)+2)/(√(x+3)-2)*(√(x+3)+2)=)=(x-1)(√(x+3)+2)/(x+3-4)=√(x+3)+2;
34/(1+4√2-√2)=34(1-3√2)/((1+3√2)(1-3√2))=34(1-3√2)/(1-18)=2(3√2-1).
4
x^2=(√5-2)√(9+4√5)=√((√5-2)^2*(9+4√5))=√((5-4√5+4)*(9+4√5))=√(81-16*5)=1;
x=+-1.
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Answers & Comments
0,2*10*√3+8/4√3+4√3=8√3;
(2√5+1)(√45-2)= 6*5+3√5-4√5-2=28-√5;
(2+√5)^2-(√5-3)^2=4+4√5+5-(5-6√5+9)=10√5-5=5*(√5-1);
2.
(√14-7)/(2-√14)=√7(√2-√7)/(√2(√2-√7))=√7/√2=√3,5;
(√3)^3-(√a)^3/((-1)(√3-√a))= (√3-√a)*(3-√3a+a)/((-1)(√3-√a))= √3a-3-a.
3
5*(2√2+√3)/((2√2-√3)((2√2+√3))=5*(2√2+√3)/(4*2-3)=2√2+√3;
(x-1)/(√(x+3)-2)=(x-1)(√(x+3)+2)/(√(x+3)-2)*(√(x+3)+2)=)=(x-1)(√(x+3)+2)/(x+3-4)=√(x+3)+2;
34/(1+4√2-√2)=34(1-3√2)/((1+3√2)(1-3√2))=34(1-3√2)/(1-18)=2(3√2-1).
4
x^2=(√5-2)√(9+4√5)=√((√5-2)^2*(9+4√5))=√((5-4√5+4)*(9+4√5))=√(81-16*5)=1;
x=+-1.