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lera1033
@lera1033
July 2022
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решите пожалуйстаа))
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kosmorez
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а) 4а-3ab+b-(8a^2b + 4ab^3-12ab-2a-b^2+3)= 4a-3ab+b-8a^2b-4ab^3+12ab+2a+b^2-3 = 6a+9ab+b+b^2-8a^2b-4ab^3-3
б) 4(2x-3)(5-x)-3(2x+1)^2= 4(10x-2x^2-15+3x)-3(4x^2+4x+1)= 40x-8x^2-60+12x-12x^2-12x-3= 40x-20x^2-63
в) 3(x^3-x^2-x+x^2-x-1)=3x^3-6x-3
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Answers & Comments
а) 4а-3ab+b-(8a^2b + 4ab^3-12ab-2a-b^2+3)= 4a-3ab+b-8a^2b-4ab^3+12ab+2a+b^2-3 = 6a+9ab+b+b^2-8a^2b-4ab^3-3
б) 4(2x-3)(5-x)-3(2x+1)^2= 4(10x-2x^2-15+3x)-3(4x^2+4x+1)= 40x-8x^2-60+12x-12x^2-12x-3= 40x-20x^2-63
в) 3(x^3-x^2-x+x^2-x-1)=3x^3-6x-3