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suzy001
@suzy001
July 2022
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решите пожалуйстаа)
(t^2+8t)^2+19(t^2+8t)+84=0
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Yena
(t²+8t)²+19(t²
+8t)+84=0
введем замену переменной
t²+8t=a
a²+19a+84=0
D=361-336=25
a
₁=(-19-5)/2=-12
a₂=(-19+5)/2=-7
Вернемся к замене переменной
1) a
₁=-12
t²+8t=-12
t²+8t+12=0
D=64-48=16
x
₁=(-8-4)/2=-6
x₂=(-8+4)/2=-2
2) a₂=-7
t²+8t=-7
t²+8t+7=0
D=64-28=36
x₁=(-8-6)/2=-7
x₂=(-8+6)/2=-1
Ответ: -7; -6; -2; -1
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Answers & Comments
введем замену переменной t²+8t=a
a²+19a+84=0
D=361-336=25
a₁=(-19-5)/2=-12
a₂=(-19+5)/2=-7
Вернемся к замене переменной
1) a₁=-12
t²+8t=-12
t²+8t+12=0
D=64-48=16
x₁=(-8-4)/2=-6
x₂=(-8+4)/2=-2
2) a₂=-7
t²+8t=-7
t²+8t+7=0
D=64-28=36
x₁=(-8-6)/2=-7
x₂=(-8+6)/2=-1
Ответ: -7; -6; -2; -1